Go Math! Practice Fluency Workbook Grade 6 Chapter 2 Factors and Multiples Exercise 2.1 Answer Key

by

Go Math! Practice Fluency Workbook Grade 6 California 1st Edition Chapter 2 Factors and Multiples

Page 7 Problem 1 Answer

A number is given to us 5.

We have to find all the factors of the given number.

The factors of the given number are: => 5, 1

Page 7 Problem 2 Answer

A number is given to us 15.

We have to find all the factors of the given number.

The factors of the given number are: 15,5,3,1

Page 7 Problem 3 Answer

A number is given to us 60.

We have to find all the factors of the given number.

The factors of the given number are: 60,30,20,15,12,10,6,5,4,3,2,1

Go Math! Practice Fluency Workbook Grade 6 Chapter 2 Factors and Multiples Exercise 2.1 Answer Key

Page 7 Problem 4 Answer

A number is given to us 6.

We have to find all the factors of the given number.

The factors of the given number are: 6,3,2,1

Page 7 Problem 5 Answer

A number is given to us 12.

We have to find all the factors of the given number.

The factors of the given number are: 12,6,4,3,2,1

Page 7 Problem 6 Answer

A number is given to us 36.

We have to find all the factors of the given number.

The factors of the given number are: 36,18,12,9,6,4,3,2,1

Page 7 Problem 7 Answer

Numbers are given to us 6,9.

We have to find the GCD of the given numbers.

The GCD of the given numbers is:3

Page 7 Problem 8 Answer

Numbers are given to us 4,8.

We have to find the GCF of the given numbers.

The factors of the given numbers are: ​4=2×2×1, 8=2×2×2×1
​

So the GCF of the given numbers is:  2×2×1=4

The GCF of the given numbers is: 4

Page 7 Problem 9 Answer

Numbers are given to us 8,12.

We have to find the GCF of the given numbers.

The factors of the given numbers are:

​8=2×2×2×1
12=3×2×2×1
​

So the GCF of the given numbers is:

​2×2×1 ⇒4
​
The GCF of the given numbers is: 4

Page 7 Problem 10 Answer

Numbers are given to us 6,15.

We have to find the GCF of the given numbers.

The factors of the given numbers are:

​6=3×2×1
15=5×3×1
​

So the GCF of the given numbers is: 3

The GCF of the given numbers is: 3

Page 7 Problem 11 Answer

Numbers are given to us10,15.

We have to find the GCF of the given numbers.

The factors of the given numbers are:

​10=5×2×1
15=5×3×1
​

So the GCF of the given numbers is: 5×1=5

The GCF of the given numbers is: 5

Page 7 Problem 12 Answer

Numbers are given to us 9,12.

We have to find the GCF of the given numbers.

The factors of the given numbers are:

​9=3×3×1
12=3×2×2×1
​

So the GCF of the given numbers is 3×1=3

The GCF of the given numbers is: 3

Page 7 Problem 13 Answer

Sum of numbers if given to us44+40.

We have to rewrite the sum as the product of GCF and a new sum.

The factors of the numbers are:

​44=11×2×2×1
40=5×2×2×2×1
​

So the GCF is: 2×2×1=4

Now rewriting the sum: 44+40=4×(11+10)

The given sum can also be written as: 44+40=4×(11+10)

Page 7 Problem 14 Answer

Sum of numbers if given to us15+81 .

We have to rewrite the sum as the product of GCF and a new sum.

The factors of the numbers are:

​15=5×3×1
81=3×3×3×3×1
​

So the GCF is: 3×1=3

Now rewriting the sum: 15+81=3×(5+27)

The given sum can also be written as: 15+81=3×(5+27)

Page 7 Problem 15 Answer

Sum of numbers if given to us13,52.

We have to rewrite the sum as the product of GCF and a new sum.

The factors of the numbers are:

​13=13×1
52=13×2×2×1
​

So the GCF is:
13×1=13

Now rewriting the sum: 13+52=13×(1+4)

The given sum can also be written as: 13+52=13×(1+4)

Page 7 Problem 16 Answer

Sum of numbers if given to us is 64,28.

We have to rewrite the sum as the product of GCF and a new sum.

The factors of the numbers are:

​64=2×2×2×2×2×2×1
28=7×2×2×1
​

So the GCF is: 2×2×1=4

Now rewriting the sum: 64+28=4×(16+7)

The given sum can also be written as: 64+28=4×(16+7)

Page 7 Problem 17 Answer

The data about beads in necklaces are given to us. We have to find now many necklaces that can be made from the given number of beads and how many beads are there in every necklace.

The GCF of the number of beads is:

​24=3×2×2×2×1
30=5×3×2×1
​⇒3×2×1=6

So the number of necklaces is six.

Now the number of individual beads are:

​24/6 =4 Jade beads
30/6 =5 Teak beads
​
The total number of necklaces that can be made from the beads is 6.

There will be4 Jade beads and 5 teak beads in each of the necklace.

Page 7 Problem 18 Answer

The data about a marine-life store is given to us.We have to find the greatest number of tanks that can be set up, that contain equal number of fishes.

The GCF of the number of fishes is:

​12=3×2×2×1
24=3×2×2×2×1
30=5×3×2×1
​⇒3×2×1=6

A total of6 tanks can be set up in the marine-life store.

Page 8 Exercise 1 Answer

Numbers are given to us 32,48.

We have to find the GCF of the given numbers.

The factors of the given numbers are:

​32=2×2×2×2×2×1
48=3×2×2×2×2×1
​

So the GCF of the given numbers is:

2×2×2×2×1=16

The GCF of the given numbers is: 16

Page 8 Exercise 2 Answer

Numbers are given to us 18,36.

We have to find the GCF of the given numbers.

The factors of the given numbers are:

​18=3×3×2×1
36=3×3×2×2×1
​

So the GCF of the given numbers is:

3×3×2×1=18

The GCF of the given numbers is:18

Page 8 Exercise 3 Answer

Numbers are given to us 28,56,84.

We have to find the GCF of the given numbers.

The factors of the given numbers are:

​28=7×2×2×1
56=7×2×2×2×1
84=7×3×2×2×1
​

So the GCF of the given numbers is: 7×2×2×1=28

The GCF of the given numbers is: 28

Page 8 Exercise 4 Answer

Numbers are given to us 30,45,75.

We have to find the GCF of the given numbers.

The factors of the given numbers are:

​30=5×3×2×1
45=5×3×3×1
75=5×5×3×1
​

So the GCF of the given numbers is: 5×3×1=15

The GCF of the given numbers is: 15

Page 8 Exercise 5 Answer
Sum of numbers if given to us is 9,15.

We have to rewrite the sum as the product of GCF and a new sum.

The factors of the numbers are:

​9=3×3×1
15=5×3×1
​

So the GCF is 3×1=3

Now rewriting the sum: 9+15=3×(3+5)

The given sum can also be written as: 9+15=3×(3+5)

Page 8 Exercise 6 Answer

Sum of numbers if given to us100+350.

We have to rewrite the sum as the product of GCF and a new sum.

The factors of the numbers are:

​100=5×5×2×2×1
350=7×5×5×2×1
​

So the GCF is: 5×5×2×1=50

Now rewriting the sum: 100+350=50×(2+7)

The given sum can also be written as: 100+350=50×(2+7)

 

Page 8 Exercise 7 Answer

Sum of numbers if given to us12+18+21.

We have to rewrite the sum as the product of GCF and a new sum.

The factors of the numbers are:

​12=3×2×2×1
18=3×3×2×1
21=7×3×1
​

So the GCF is 3×1=3

Now rewriting the sum: 12+18+21=3×(4+6+7)

The given sum can also be written as: 12+18+21=3×(4+6+7)

Go Math Answer Key

 

Leave a Comment