enVisionmath 2.0: Grade 6, Volume 1 Chapter 1 Algebra: Understand Numerical And Algebraic Expressions Homework And Practice 8

Chapter 1 Algebra: Understand Numerical And Algebraic Expressions

Homework And Practice 8

Page 59 Exercise 1 Answer

Step 1 → Identify the values in the formulas

P = Perimeter of the rectangle

l = length of the rectangle = 12 ft

w = width of the rectangle = 8 ft

Step 2 → Substitute the values in the formula and evaluate

P = 2l + 2w

P = 2(12) + 2(8) Substitute the value

P = 24 + 16 Simplify

P = 40 ft

The perimeter of the rectangle LMNP is 40 feet.

Result

40 feet

Read And Learn More: enVisionmath 2.0 Grade 6 Volume 1 Solutions

Page 59 Exercise 2 Answer

Step 1 → Identify the values in the formulas

A = Area of the rectangle

l = length of the rectangle = 12 ft

w = width of the rectangle = 8 ft

Step 2 → Substitute the values in the formula and evaluate

A = lw

A = (12)(8) Substitute the value

A = 96 \(ft^2\)

The area of the rectangle LMNP is 96 square feet.

Result

96 \(ft^2\)

Page 60 Exercise 3 Answer

Step 1 → Identify the values in the formulas

a = rate of acceleration

f = final speed = 77 meters per second

s = starting speed = 44 meters per second

t = time = 11 seconds

Step 2 → Substitute the values in the formula and evaluate

\(a=\left(\frac{f-s}{t}\right)\)

\(a=\left(\frac{77-44}{11}\right)\) Substitute the value

\(a=\left(\frac{33}{11}\right)\) Simplify

a = 3

The acceleration of the racecar is 3 meters per second squared.

Result

3 meters per second squared

Page 60 Exercise 4 Answer

Step 1 → Identify the values in the formulas

a = rate of acceleration

f = final speed = 26.9 meters per second

s = starting speed = 0 meters per second

t = time = 6.5 seconds

Step 2 → Substitute the values in the formula and evaluate

\(a=\left(\frac{f-s}{t}\right)\)

\(a=\left(\frac{26.9-0}{6.5}\right)\) Substitute the value

\(a=\left(\frac{26.9}{6.5}\right)\) Simplify

a = 4.13

The rate of acceleration of the car is 4.13 meters per second squared.

I do not support the claim.

Result

I do not support the claim

Page 60 Exercise 5 Answer

Cups of flour requires for one recipe = \(\frac{3}{4}\)

Cups of flour requires for other recipe = \(\frac{1}{2}\)

Total cups of flour requires

= \(\frac{3}{4}\) + \(\frac{1}{2}\)

= \(\frac{3+2}{4}\)

= \(\frac{5}{4}\)

= 1.25

Both the recipes require a total of 1.25 cups of flour and Jenna has 2 cups of flour which is enough to make both recipes.

Result

Yes, 2 cups of flour is enough to make both recipes.

Page 60 Exercise 6 Answer

P = 2l + 2w

P = 2(l) + 2(w) Using Distributive Property

P = 2(l + w) 2 is the common factor

Since both the formula P = 2l + 2w and P = 2(l + w) is equivalent.

So, Jack and Sandy both are correct.

Result

Both the formula are correct as they are equivalent

Page 60 Exercise 7 Answer

Length:

Step 1 → Identify the values in the formulas

c = measures in centimeters

f = measure in feet = 9 ft

Step 2 → Substitute the values in the formula and evaluate

c = 0.3f × 100

c = 0.3(9) × 100 Substitute the value

c = 2.7 × 100 Simplify

c = 270

Width:

Step 1 → Identify the values in the formulas

c = measures in centimeters

f = measure in feet = 5 ft

Step 2 → Substitute the values in the formula and evaluate

c = 0.3f × 100

c = 0.3(5) × 100 Substitute the value

c = 1.5 × 100 Simplify

c = 150

Result

Dimension of rectangle in centimeter:

Length = 270 cm and Width = 150 cm

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