Go Math! Practice Fluency Workbook Grade 6 California 1st Edition Chapter 4 Operations with Fractions
Page 21 Problem 1 Answer
Given :- a mixed number 10×1/2
Find:- The reciprocal of the given number and confirm number and reciprocal multiplication is one. First, convert the mixed number in improper fraction and take reciprocal of the fraction.
Given in the question a expression in form of mixed number.
First, convert mixed fraction in improper fraction and then take the reciprocal of the term .
expression in form of improper fraction is 10×1/2 = 21/2
Reciprocal of the 10×1/2 is 2/21 And we proved multiplication of both terms is one.
Page 21 Problem 2 Answer
Given :- a mixed number 6×3/7
Find:- The reciprocal of the given number and confirm number and reciprocal multiplication is one .First convert the mixed number in improper fraction and take reciprocal of the fraction.
Given in the question a expression in form of mixed number .
First, convert mixed fraction in improper fraction and then take the reciprocal of the term .
expression in form of improper fraction is 6×3/7 = 45/7
Reciprocal of the 6×3/7 is 7/45 And we proved the multiplication of both term is one.
Page 21 Problem 3 Answer
Given :- a mixed number 2×8/9
Find:- The reciprocal of the given number and confirm number and reciprocal multiplication is one. First convert the mixed number in improper fraction and take reciprocal of the fraction.
Given in the question a expression in form of mixed number.
First, convert mixed fraction in improper fraction and then take the reciprocal of the term.
expression in form of improper fraction is 2×8/9=26/9
Reciprocal of the expression 2×8/9 is 6/29 And we proved multiplication of both term is one.
Go Math Grade 6 Exercise 4.3 Operations With Fractions Solutions
Page 21 Problem 4 Answer
Given :- a mixed number 15×1/4
Find:- The reciprocal of the given number and confirm number and reciprocal multiplication is one .First convert the mixed number in improper fraction and take reciprocal of the fraction.
Reciprocal of the term 61/4 is 4/61 And we proved multiplication of both term is one.
Page 21 Problem 5 Answer
Given :- a mixed number 9×2/3
Find:- The reciprocal of the given number and confirm number and reciprocal multiplication is one .First convert the mixed number in improper fraction and take reciprocal of the fraction.
Reciprocal of the expression 9×2/3 = 2/29 And we proved multiplication of both terms is one .
Page 21 Problem 6 Answer
Given :- a expression 7×5/8
Find:- The reciprocal of the given number and confirm number and reciprocal multiplication is one .First convert the mixed number in improper fraction and take reciprocal of the fraction.
Reciprocal of the expression 7×5/8 is 8/61 And we proved the multiplication of both terms is one .
Page 21 Problem 7 Answer
Given :- a expression 8/10÷1×5/6
Find:- The simplest form of the given expression .First convert the mixed fraction in improper fraction then multiply the first fraction by reciprocal of the second fraction.
Simplest form of the expression 8/10÷1×5/6 is 24/55.
Page 21 Problem 8 Answer
Given :- a expression 2÷1×6/7
Find:- The simplest form of the given expression .First convert the mixed fraction in improper fraction then multiply the first fraction by reciprocal of the second fraction.
Simplest form of the expression is 2÷1×6/7=1×1/13.
Page 21 Problem 9 Answer
Given :- a expression 3×3/5÷2×1/4
Find:- The simplest form of the given expression First convert the mixed fraction in improper fraction then multiply the first fraction by reciprocal of the second fraction.
Simplest form of the expression 3×3/5÷2×1/4 is 1×11/25.
Page 21 Problem 10 Answer
Given :- a expression 4×1/2÷2×3/8
Find:- The simplest form of the given expression .First convert the mixed fraction in improper fraction then multiply the first fraction by reciprocal of the second fraction.
Simplest form of the expression 4×1/2÷2×3/8 is 1×17/19.
Page 21 Problem 11 Answer
Given :- a expression 5×5/6÷3×1/6
Find:- The simplest form of the given expression.First, convert the mixed fraction in improper fraction then multiply the first fraction by reciprocal of the second fraction.
Simplest form of the 5×5/6÷3×1/6 =1×16/19.
Page 21 Problem 12 Answer
Given :- a expression 11/12÷2×5/8
Find :- The simplest form of the given expression .First convert the mixed fraction in improper fraction then multiply the first fraction by reciprocal of the second fraction.
Simplest form of the expression 11/12÷2×5/8 is 22/63
Go Math Grade 6 Exercise 4.3 Operations With Fractions Answers
Page 21 Problem 13 Answer
Given :- a expression 1×9/13÷3/8
Find:- The simplest form of the given expression .First convert the mixed fraction in improper fraction then multiply the first fraction by reciprocal of the second fraction.
Simplest form of the expression 1×9/13÷3/8 is 4×20/39
Page 21 Problem 14 Answer
Given :- a expression 6×4/5÷3×2/9
Find :- The simplest form of the given expression.First, convert the mixed fraction in improper fraction then multiply the first fraction by reciprocal of the second fraction.
Simplest form of the expression 6×4/5÷3×2/9 is 68/145.
Page 21 Problem 15 Answer
Given :- a expression 9×2/3÷6×8/9
Find :- The simplest form of the given expression. First, convert the mixed fraction in improper fraction then multiply the first fraction by reciprocal of the second fraction.
Simplest for of the expression 9×2/3÷6×8/9 is 1 25/62.
Page 21 Problem 16 Answer
Given:- Area of the concrete is 36×5/6 and the width of the concrete is 5×2/3
Find :- picnic table is 7foot, table would fit along the diagonal.
We need to find the length of the concrete by formula area=length ×width.
Length of the concrete is 6.5ft and length of the table is 7ft so we can table would fit along the diagonal.
Page 21 Problem 17 Answer
Given:- Width of the mirror is 13×3/4 inches and area of the mirror is 225 square inches.
Find:- we can feet mirror in place of 15 inches by16 inches.
We need to find the length of the mirror by Area=length ×width.
Length of the mirror is 16.36 inches and the mirror space is 15 by 16 inches So we can’t feet mirror in given space.
Page 21 Problem 18 Answer
Given :- Barney has 16×1/5 yd fabric and for one costume she need 5×2/5
Find:- how many costumes she makes by the 16×1/5 yd fabric.
We need to divide the total fabric by the fabric used in one costume and get the answer.
She makes 3 costumes in 16×1/5 yd fabric.
Page 22 Exercise 1 Answer
Given :- a term is 9/14
Find- reciprocal of the given term .
We know the reciprocal of the x is 1/x
Given in the question a term 9/14
Reciprocal of the 9/14=14/9
By the definition of reciprocal.
Multiplication of both terms is 9/14×14/9 is 1
Reciprocal of the 9/14 is 14/9
Page 22 Exercise 2 Answer
Given :- a term 3×1/2
Find:- the reciprocal of the term .
First, we need to convert the mixed in improper fraction .and then take reciprocal.
Multiplication of both terms is 7/2×2/7=1
Reciprocal of the term 3×1/2=2/7.
Page 22 Exercise 3 Answer
Given reciprocal is 10×2/3
To do: Find the given reciprocal
The reciprocal of 10×2/3 is 3/32.
Page 22 Exercise 4 Answer
Given a division
To do: Complete the given division in the simplest form
Page 22 Exercise 5 Answer
Given a division
To do: Complete the given division in the simplest form.
Solutions For Go Math Grade 6 Exercise 4.3 Operations With Fractions
Page 22 Exercise 6 Answer
Given a division
To do: Complete the given division in the simplest form
Page 22 Exercise 7 Answer
Given a division
To do: Complete the given division in the simplest form
The result of the given division is 6×1/4
Page 22 Exercise 8 Answer
Given a division
To do: Complete the given division in the simplest form.
The result of the given division is 7/16.
Go Math Grade 6 Operations With Fractions Exercise 4.3 Key
Page 22 Exercise 9 Answer
Given a division
To do: Complete the given division in the simplest form.
The result of the given division is 1×2/3.
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