Go Math! Practice Fluency Workbook Grade 6 Chapter 3 Rational Numbers Exercise 3.2 Answer Key

by

Go Math! Practice Fluency Workbook Grade 6 California 1st Edition Chapter 3 Rational Numbers

Page 13 Problem 1 Answer

We have given the number as 3.5 Asked to graph each number and its opposite on a number line.

To get the required number we first find the opposite of the given number by multiplying the negative sign with it.

Then mark the numbers that are opposite of each other on the given graph.

We have given the number as 3.5

We get the opposite of the given number as −3.5

For the given number 3.5

we get the opposite of it −3.5 and numbers on the line as

Go Math! Practice Fluency Workbook Grade 6, California 1st Edition, Chapter 3 Rational Numbers 1

Page 13 Problem 2 Answer

We have given the number as −2.5 and Asked to graph each number and its opposite on a number line.

To get the required number we first find the opposite of the given number by multiplying the negative sign with it.

Go Math! Practice Fluency Workbook Grade 6 Chapter 3 Rational Numbers Exercise 3.2 Answer Key

Then mark the numbers that are opposite of each other on the given graph.

We have given the number as 2.5

We get the opposite of the given number as
​−(−2.5)
=2.5

​For the given number −2.5

we get the opposite number as 2.5 and on the num

Go Math! Practice Fluency Workbook Grade 6, California 1st Edition, Chapter 3 Rational Numbers 2

Page 13 Problem 3 Answer

We have given the number as 2×1/2 Asked to graph each number and its opposite on a number line.

To get the required number we first find the opposite of the given number by multiplying the negative sign with it.

Then mark the numbers that are opposite of each other on the given graph.

For the given number 2×1/2

we get the opposite number as −2×1/2 and on the number line as

Go Math! Practice Fluency Workbook Grade 6, California 1st Edition, Chapter 3 Rational Numbers 3

Page 13 Problem 4 Answer

We have given the number as −1×1/2 Asked to graph each number and its opposite on a number line.

To get the required number we first find the opposite of the given number by multiplying the negative sign with it.

Then mark the numbers that are opposite of each other on the given graph.

For the given number −1×1/2, we get the opposite number as 1×1/2 and on the number line a

Go Math! Practice Fluency Workbook Grade 6, California 1st Edition, Chapter 3 Rational Numbers 4

Page 13 Problem 5 Answer

We have given the number as 4.25 and Asked to name the opposite of the given number.

To get the required number we first find the opposite of the given number by multiplying the negative sign with it.

Then on solving the sign convention, we will get the required opposite number. We have given the number as 4.25

We get the opposite of the number as −4.25

For the given number 4.25

we get the opposite of it as −4.25

Page 13 Problem 6 Answer

We have given the number as −5×1/4 and Asked to name the opposite of the given number.

To get the required number we first find the opposite of the given number by multiplying the negative sign with it.

Then on solving the sign convention, we will get the required opposite number.

We have given the number as

⇒ \(-5 \frac{1}{4}\)

We get the opposite of the number as

⇒ \(-\left(-5 \frac{1}{4}\right)\)

⇒ \(5 \frac{1}{4}\)

For the given number −5×1/4

we get the opposite of it as 5×1/4

Page 13 Problem 7 Answer

We have given the number as 1/2 and Asked to name the opposite of the given number.

To get the required number we first find the opposite of the given number by multiplying the negative sign with it.

Then on solving the sign convention, we will get the required opposite number.

For the given number 1/2

we get the opposite of it as −1/2

Page 13 Problem 8 Answer

We have given the number as 2×1/3 Asked to Name the absolute value of the given number.

Here to get the absolute value of the given number we just have to write the numerical part of the number.

We have given the number as

⇒ \(2 \frac{1}{3}\)

We get the absolute of the number as

⇒ \(\left|2 \frac{1}{3}\right|\)

⇒ \(2 \frac{1}{3}\)

For the given number 2×1/3

we get the absolute of it as 2×1/3

Page 13 Problem 9 Answer

We have given the number −3.85 and Asked to Name the absolute value of the given number.

Here to get the absolute value of the given number we just have to write the numerical part of the number.

We have given the number as −3.85

We get the absolute of the number as ​∣−3.85∣ =3.85

For the given number −3.85

we get the absolute of it as 3.85

Page 13 Problem 10 Answer

We have given the number as −6.1 and Asked to Name the absolute value of the given number.

Here to get the absolute value of the given number we just have to write the numerical part of the number.

We have given the number as−6.1

We get the absolute of the number as​ ∣−6.1∣ =6.1

For the given number −6.1

we get the absolute of it as 6.1

Page 13 Problem 11 Answer

Given:- The elevations of checkpoints along a marathon route in a table

To Find:- To determine the opposite values of each checkpoint elevation

The elevation of checkpoints A, B, C.D, and E are 15.6,17.1,5.2,−6.5,−18.5 feet respectively.

The opposite values of the checkpoints A, B, C, D, and E would be −15.6,−17.1,−5.2,6.5,18.5 feet respectively.

The opposite values of the checkpoints A, B, C, D, and E would be 15.6,−17.1,−5.2,6.5,18.5 feet respectively.

Page 13 Problem 12 Answer

Given:- The elevations of checkpoints along a marathon route in a table

To Find:- To determine the checkpoint which is closest to the sea level

The elevation of any point is considered from the sea level which would be at 0 feet.

So, the checkpoint that would be closest to the sea level would be the smallest value or the smallest absolute value of the data given in the table.

From the data given in the table, we can notice that the smallest value and the checkpoint that would be closest to the sea level would be 5.2 feet at checkpoint C.

The checkpoint that would be closest to the sea level would be at checkpoint C at 5.2 feet.

Page 13 Problem 13 Answer

Given:- The elevations of checkpoints along a marathon route in a table

To Find:- To determine the checkpoint which is furthest from the sea level

The elevation of any point is considered from the sea level which would be at 0 feet.

So, the checkpoint that would be furthest from the sea level would be the largest value or the largest absolute value of the data given in the table.

From the data given, the absolute values of the checkpoints A, B, C, D, and E are 15.6,17.1,5.2,6.5,18.5.

Therefore, we can conclude from the absolute values of the data given that Checkpoint E at 18.5 feet would be the furthest from the sea level.

The checkpoint that would be furthest from the sea level would be at checkpoint E at 18.5 feet.

Page 14 Exercise 1 Answer

Given:- Are the opposite of −6.5 and the absolute value of −6.5 the same?

To Find:- To determine whether the opposite and the absolute value of the given number −6.5 are the same or not

We know that the opposite value of a negative number would always be positive of the same number. So, the opposite of −6.5 would be 6.5.

We also know that the absolute value of a number is always positive. So, the absolute value of −6.5 would be 6.5.

Therefore, the opposite and the absolute value of the given number−6.5 are the same.

The opposite and the absolute value of the given number−6.5 are the same.

Page 14 Exercise 2 Answer

Given:- Are the opposite of 3×2/5 and the absolute value of 3×2/5 the same?

To Find:- To determine whether the opposite and the absolute value of the given fraction or mixed number are the same We know that the opposite value of a positive number would always be negative of the same number. So, the opposite of 3×2/5 would be−3×2/5.

We also know that the absolute value of a number is always positive. So, the absolute value of 3×2/5 would be 3×2/5.

Therefore, we can clearly say that the opposite and the absolute value of the mixed fraction 3×2/5 are not the same.

The opposite and the absolute value of the mixed fraction 3×2/5 are not the same.

Page 14 Exercise 3 Answer

Given:- Write a rational number whose opposite and absolute value are the same

To Find:- To write the example of a rational number whose opposite and absolute value are the same and to given the appropriate explanation We know that the opposite value of a positive number would always be negative of the same number and the opposite value of a negative number would be positive of the same number.

Also, the absolute value of a number is always positive. So, we can say that the opposite value and the absolute value of any number would be positive and the same.

For example, the absolute value and the opposite of the number 5.5 would be 5.5.

The rational number whose opposite and absolute values are the same are−5.5 which would be 5.5

Page 14 Exercise 4 Answer

Given:- Write a rational number whose opposite and absolute values are opposite

To Find:- To write the example of a rational number whose opposite and absolute value are opposite and to give the appropriate explanation

We know that the opposite value of a positive number would always be negative of the same number and the opposite value of a negative number would be positive of the same number.

Also, the absolute value of a number is always positive. So, we can say that a rational number whose opposite and absolute values are opposite would be any positive number.

For example, the opposite value of the rational number 5.5 would be − 5.5. At the same time, the absolute value of the same rational number 5.5 is 5.5.

The rational number whose opposite and absolute values are not the same or opposite is 5.5

Go Math Answer Key

 

Leave a Comment