enVisionmath 2.0: Grade 6, Volume 1 Chapter 1 Algebra: Understand Numerical And Algebraic Expressions Review

Chapter 1 Algebra: Understand Numerical And Algebraic Expressions

Review What You Know

Page 2 Exercise 1 Answer

A formula is a rule that connects two or more quantities using symbols. Therefore, the word that goes on the blank is formula.

Result

formula

Page 2 Exercise 2 Answer

A(n) numerical expression is a mathematical phrase that includes numbers and at least one operations.

Result

NUMERICAL EXPRESSION

Read And Learn More: enVisionmath 2.0 Grade 6 Volume 1 Solutions

Page 2 Exercise 3 Answer

A quantity that is unknown may be represented by a(n) variable.

Result

VARIABLE

Page 2 Exercise 4 Answer

56 − 27 + (16 ÷ 4) Evaluate

= 56 − 27 + 4 Solve parentheses

= 29 + 4 Subtract

= 33 Add

Result

33

Page 2 Exercise 5 Answer

94 − (5 × 6) ÷ 6 × 11 Evaluate

= 94 − 30 ÷ 6 × 11 Solve Parentheses

= 94 − 5 × 11 Divide

= 94 − 55 Multiply

= 39 Subtract

Result

39

Page 2 Exercise 6 Answer

[21 ÷ 3] + (18 ÷ 6) Evaluate

= 7 + (18 ÷ 6) Solve square brackets

= 7 + 3 Solve parentheses

= 10 Add

Result

10

Page 2 Exercise 7 Answer

2 × 36 − (12 + 7) Evaluate

= 2 × 36 − 19 Solve parentheses

= 72 − 19 Multiply

= 53 Simplify

Result

53

Page 2 Exercise 8 Answer

12 ÷ (2 + 1) × 15 ÷ 3 Evaluate

= 12 ÷ 3 × 15 ÷ 3 Solve Parentheses

= 4 × 5 Divide

= 20 Multiply

Result

20

Page 2 Exercise 9 Answer

15 − (2 × 3) × 2 + 9 Evaluate

= 15 − 6 × 2 + 9 Solve Parentheses

= 15 − 12 + 9 Multiply

= 3 + 9 Subtract

= 12 Add

Result

12

Page 2 Exercise 10 Answer

Length = 13 cm ; Width = 13 cm

Perimeter

= 2l + 2w

= 2(13) + 2(13) Substitute the value

= 26 + 26 Multiply

= 52 cm

Area

= lw

= (13)⋅(13) Substitute the value

= 169 sq. cm

Result

P = 52 cm

A = 169 cm2

Page 2 Exercise 11 Answer

Length = 21 in ; Width = 5 in

Perimeter

= 2l + 2w

= 2(21) + 2(5) Substitute the value

= 42 + 10 Multiply

= 52 in

Area

= lw

= (21) ⋅ (5) Substitute the value

= 105 sq. in

Result

P = 52 in

A = 105 in2

Page 2 Exercise 12 Answer

Length = 15 m ; Width = 9 m

Perimeter

= 2l + 2w

= 2(15) + 2(9) Substitute the value

= 30 + 18 Multiply

= 48 m

Area = lw

= (15)⋅(9) Substitute the value

= 135 sq. m

Result

P = 48 m

A = 135 m2

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