Cengage Financial Algebra 1st Edition Chapter 2 Exercise 2.1 Modeling a Business

Financial Algebra 1st Edition Chapter 2 Modeling a Business

Page 66 Problem 1 Answer

Given: A local coffee shop sells hot chocolate.

The manager keeps track of the temperature for the entire year and the hot chocolate sales.

A scatterplot is graphed with temperature on the horizontal axis and hot chocolate sales on the vertical ax

To find; Do you think the scatterplot shows a positive or negative correlation? Is there causation? Explain.

As the temperature rises, the hot chocolate sales generally decrease

So, there is a correlation between the data.

Because the y-values increase when the x-values decreases ,the correlation is negative

Additionally, the rise in temperature caused the decreased in the number of hot chocolate sold.

Therefore,the temperature is the explanatory variable and the number of hot c

Hence we conclude that the temperature is the explanatory variable and the number of hot chocolate  is the response variable

Page 67 Problem 2 Answer

Given: negative correlation but there is no causation

To find; Think of an example of data that might have a negative correlation but there is no causation.

let suppose The scatter plot at the right shows the relationship between the number of text messages made by each of ten juniors while studying for Mr. Patel chemistry test last week and their scores on the test.

As the number of text messages increases, test grades do not increase,

so there is no positive correlation.

As the number of text messages increases, test grades do not decrease,

so there is  negative correlation. There is no trend in the data, so there is no correlation

Another example for negative correlation are

Cengage Financial Algebra 1st Edition Chapter 2 Exercise 2.1 Modeling a Business

Possible examples could then be:- Amount of water remaining in a pool and the number of minutes the pool has been draining.

The amount of money owed on a loan and the number of months making payments.

The distance from home and the number of minutes walking from school to home.

Hence we conclude that there is a negative correlation. There is no trend in the data, so there is no correlation

Page 67 Problem 3 Answer

Given; Students in a biology class measure the circumference and diameter of every tree on the school property.

The students create a table of ordered pairs and plan to draw a scatterplot.

To find; Should there be a positive correlation, a negative

A scatter plot (aka scatter chart, scatter graph) uses dots to represent values for two different numeric variables.

The position of each dot on the horizontal and vertical axis indicates values for an individual data point.

Scatter plots are used to observe relationships between variables.

The example scatter plot above shows the diameters and heights for a sample of fictional trees.

Each dot represents a single tree; each point’s horizontal position indicates that tree’s diameter (in centimeters) and the vertical position indicates that tree’s height (in meters).

Financial Algebra, 1st Edition, Chapter 2 Modeling a Business 3

From the plot, we can see a generally tight positive correlation between a tree’s diameter and its height.

We can also observe an outlier point, a tree that has a much larger diameter than the others.

This tree appears fairly short for its girth, which might warrant further investigation.

Hence we conclude that From the plot, we can see a generally tight positive correlation between a tree’s diameter and its height.

Page 68 Problem 4 Answer

Given: statement about the bussiness

To find:  here we have explain how the quote can be interpreted by a business person

Here gieving with some example “To guess is cheap” implies that making a guess doesn’t cost you a lot, because you can use little resources in order to make a guess and thus it won’t cost you a lot of money to make a guess about something.

However, if you guess wrongly, then it could become very expensive.

Because if you invest a lot of money in your guess and your guess was incorrect, then you could potentially lost a lot of your money (or even all of your money) and guessing wrongly thus could be expensive.

Here we conclude that Making a guest doesn’t cost a lot of money, but you could lose a lot of money if you guess wrongly.

Page 68 Problem 5 Answer

Given; A scatterplot shows the number of days that have passed and the number of days left in a month.

To find; Is there a positive or negative correlation? Explain.

There is a negative correlation, because if the number of days that have passed increase, the number of days that are left will decrease.

Hence we conclude that by negative correlation, the number of days that are left will decrease.

Page 68 Problem 6 Answer

Given ;

Financial Algebra, 1st Edition, Chapter 2 Modeling a Business 6

To find:  Examine each scatterplot. Identify each as showing a positive correlation, a negative correlation, or no correlation.

we have scatter plot here from the graph we see that the value of one variable increases when the value of the other increases.

so there will be positive corelation will exit

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Hence we conclude that the graph will contain positive corelation

Page 68 Problem 7 Answer

Given :

Financial Algebra, 1st Edition, Chapter 2 Modeling a Business 7

To find:  Examine each scatterplot. Identify each as showing a positive correlation, a negative correlation, or no correlation.

we have Here we see that In the given scatterplot, we note that the pattern slopes downwards and thus we have a negative correlation.

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Hence we conclude that the pattern slopes downwards and thus we have a negative correlation.

Page 68 Problem 8 Answer

Given :

Financial Algebra, 1st Edition, Chapter 2 Modeling a Business 8

To find: Examine each scatterplot. Identify each as showing a positive correlation, a negative correlation, or no correlation.

we have Here we see that from the graph No correlation, exist  because if you sketch a line through the given points, this line will be horizontal (or have a zero slope) and thus the data contains no correlation.

Financial Algebra, 1st Edition, Chapter 2 Modeling a Business 8 1

Hence we conclude that the graph No correlation, exist  because if you sketch a line through the given points, this line will be horizontal and thus the data contains no correlation.

Page 68 Problem 9 Answer

Given ;

Financial Algebra, 1st Edition, Chapter 2 Modeling a Business 9

To find; Examine each scatterplot. Identify each as showing a positive correlation, a negative correlation, or no correlation

we have From the graph we see that because if you sketch a line through the given points, this line will be descending (or have a negative slope) and thus the data contains a negative correlation.

Financial Algebra, 1st Edition, Chapter 2 Modeling a Business 9 1

Hence we conclude that the graph will contain negative correlation as the slope the line are descending .

Page 68 Problem 10 Answer

Given ;

Financial Algebra, 1st Edition, Chapter 2 Modeling a Business 10

To find ;  Examine each scatter plot. Identify each as showing a positive correlation, a negative correlation, or no correlation.

we have given graph

Financial Algebra, 1st Edition, Chapter 2 Modeling a Business 10 1

Here if we see from the graph we conclude that  if you sketch a line through the given points, this line will be descending (or have a negative slope) and thus the data contains a negative correlation.

Hence the graph will contain negative corelation as given points, the line are descending

Page 68 Problem 11 Answer

Given ;

Financial Algebra, 1st Edition, Chapter 2 Modeling a Business 11

To find ; Examine each scatterplot. Identify each as showing a positive correlation, a negative correlation, or no correlation.

we have

Financial Algebra, 1st Edition, Chapter 2 Modeling a Business 11 1

Here we see form the graph that there will be No correlation, because if you sketch a line through the given points, this line will be horizontal (or have a zero slope) and thus the data contains no correlation.

Hence we conclude that there will be no relation will exist the data contains no correlation.

Page 68 Problem 12 Answer

Given: the personal income per capita (per person) in the United States for seven selected years.

To find; Draw a scatterplot for the data.

Financial Algebra, 1st Edition, Chapter 2 Modeling a Business 12

As the x-values increase, the y-values decrease.

Therefore, this scatterplot shows a negative correlation between the two variables.

Financial Algebra, 1st Edition, Chapter 2 Modeling a Business 12 1

Hence we see tha scatter plot this scatterplot shows a negative correlation between the two variables.

Page 68 Problem 13 Answer

Given ; The table shows the personal income per capita (per person) in the United States for seven selected years.

To find; Describe the correlation.

As the x-values increase, the y-values decrease.

Therefore, this scatterplot shows a negative correlation between the two variables.

The year is on the x−axis and the per capita income in dollars is on the y−axis.

Financial Algebra, 1st Edition, Chapter 2 Modeling a Business 13

The graph indicates a positive correlation, because the points in the scatterplot slope upwards, or in other words, if you sketch a line through the given points, this line will be ascending (have a positive slope).

Hence we conclude that The year is on the x−axis and the per capita income in dollars is on the y−axis.

Financial Algebra, 1st Edition, Chapter 2 Modeling a Business 13 1

The graph indicates a positive correlation, because the points in the scatterplot slope upwards, or in other words, if you sketch a line through the given points, this line will be ascending (have a positive slope).

Page 69 Exercise 1 Answer

Given ; ​

​(100,4),(100,4),(100,3),(250,3),(250,2),(250,2)

(500,1),(500,2),(500,1),(1,000,1),(1,000,2),(1,000,1)

Twelve people were given different daily doses of vitamin C, in milligrams, for a year

To find; Construct a scatterplot.

Financial Algebra, 1st Edition, Chapter 2 Modeling a Business

The daily dose of vitamin C is on the x-axis and the number of colds is on the y-axis

Financial Algebra, 1st Edition, Chapter 2 Modeling a Business e1

Hence we have plotted the scatter graph for ordered pairs gives the results of a science experiment.

Twelve people were given different daily doses of vitamin C

Page 69 Exercise 2 Answer

Given; They reported the number of colds they got during the year

​(100,4),(100,4),(100,3),(250,3),(250,2),(250,2)

(500,1),(500,2),(500,1),(1,000,1),(1,000,2),(1,000,1)

​To find; Describe the correla

The daily dose of vitamin C is on the x-axis and the number of colds is on the y

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Hence we see the Negative correlation, because if you sketch a line through the given points, this line will be descending (or have a negative slope) and thus the data contains a negative correlation.

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Hence we conclude that the data contains a negative correlation.

Page 69 Exercise 3 Answer

Given ; ​

​(100,4),(100,4),(100,3),(250,3),(250,2),(250,2)

(500,1),(500,2),(500,1),(1,000,1),(1,000,2),(1,000,1)

​To find : Should the scientists label the vitamin C intake the explanatory variable and the number of colds the response variable?

Explain here we see that The variable which cause the change in the other variable in the explanatory variable, while the affected variable is the response variable.

The number of colds is affected by the daily dose of vitamin C (and not the other way around), thus the daily dose of vitamin C  is the explanatory variable and the number of colds is the response variable.

Hence we conclude that yes the scientists label the vitamin C intake the explanatory variable and the number of colds the response variable

Page 69 Exercise 4 Answer

Given; If x represents the year and y represents the enrollment,

To find; draw a scatter plot to depict t

The year is on the  x axis and the enrollment is on the y-axis.

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Hence we draw a scatter plot to depict the data. by The enrollment at North Shore High School

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Page 69 Exercise 5 Answer

Given; The enrollment at North Shore High School is given in the table. In each year, the number of students on the baseball team was 19

To find; Describe the correlation from the scatter plot.

The year is on the x axis and the enrollment is on the y-axis.

Financial Algebra, 1st Edition, Chapter 2 Modeling a Business e5

The grap g shows the Positive correlation because if you sketch a line through the given points, this line will be ascending (or have a positive slope) and thus the data contains a positive correlation.

hence we conclude that the data contains a positive correlation.

Page 69 Exercise 6 Answer

Given; If x represents the enrollment and y represents the number of students on the baseball team

To find;  draw a scatterplot to depict the data.

The enrollment is on the  x -axis and the year is on the y-axis

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Hence the scatter plot for the given for the enrollment and y represent the number of students on the baseball team

Financial Algebra, 1st Edition, Chapter 2 Modeling a Business e6 1

Page 69 Exercise 7 Answer

Given; The enrollment at North Shore High School is given in the table. Each year,

To find: Describe the correlation from the scatterplot

The enrollment is on the  x-axis and the year is on the y-axis

Financial Algebra, 1st Edition, Chapter 2 Modeling a Business e7

Hence we conclude that ithe graph has a Positive correlation, because if you sketch a line through the given points, this line will be ascending (or have a positive slope) and thus the data contains a positive correlation.

Hence we cocnlude that the data contains a positive correlation.

Financial Algebra, 1st Edition, Chapter 2 Modeling a Business e7 1

Page 69 Exercise 8 Answer

Given; state’s population

To find ; . Find your state’s population for each of the last ten years.

here we will choose to use the state of america, but you could use the population of any other states instead.

I was able to find the population per year for the state but there might be other useful websites online.

 Year x ​ Population y
2010 6,355,882
2011 6,396,281
2012 6,450,632
2013 6,490,795
2014 6,540,007
2015 6,590,726
2016 6,649,404
2017 6,715,984
2018 6,782,564
2019 6,849,144

 

​​Hence we have found the population for each of the last ten years. for america

Page 69 Exercise 9 Answer

Given: Let x represent the year, and let y represent the population.

To find: Create a table of bivariate data

Here we will choose to use the population of America, but you could use the population of any country, state, city, etc. instead.

It is most often very easy to find the population of a country for a number of years online

Year x Population y
1955 8,887,274
1960 9,167,365
1965 9,443,939
1970 9,632,180
1975 9,771,586
1980 9,868,995
1985 9,916,578
1990 10,006,544
1995 10,186,305
2000 10,282,033
2005 10,546,886
2010 10,938,739
2015 11,287,940

 

Hence we created a table of bivariate data for cities ​

1955 8,887,274
1960 9,167,365
1965 9,443,939
1970 9,632,180
1975 9,771,586
1980 9,868,995
1985 9,916,578
1990 10,006,544
1995 10,186,305
2000 10,282,033
2005 10,546,886
2010 10,938,739
2015 11,287,940

 

Page 69 Exercise 10 Answer

Here we will choose to use the population of America, but you could use the population of any country, state, city, etc. instead.

It is most often very easy to find the population of a country for a number of years online

​ Year x  Population y
1955 8,887,274
1960 9,167,365
1965 9,443,939
1970 9,632,180
1975 9,771,586
1980 9,868,995
1985 9,916,578
1990 10,006,544
1995 10,186,305
2000 10,282,033
2005 10,546,886
2010 10,938,739
2015 11,287,940

 

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​Hence we conclude and scatter the plot for the given data

Financial Algebra, 1st Edition, Chapter 2 Modeling a Business e10

Page 69 Exercise 11 Answer

Here we will choose to use the state of america, but you could use the population of any other states instead.

I was able to find the population per year for the state, but there might be other useful websites online.​​

 Year x  Population y
2010 6,355,882
2011 6,396,281
2012 6,450,632
2013 6,490,795
2014 6,540,007
2015 6,590,726
2016 6,649,404
2017 6,715,984
2018 6,782,564
2019 6,849,144

 

We note that as the year increases that the population increases, which indicates that there is a positive correlation

Hence we cocclude the difference and relation between the corelation and we cocnlude that as the year increases that the population increases, which indicates that there is a positive correlation.

Chapter 2 Solving Linear Inequalities

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