Big Ideas Math Algebra 1 Student Journal 1st Edition Chapter 3 Graphing Linear Functions Exercise 3.6

Big Ideas Math Algebra 1 Student Journal 1st Edition Chapter 3 Graphing Linear Functions

 

Page 84 Essential Question  Answer

Given: The linear functions​ f(x)=x
g(x)=f(x)+c
h(x)=f(cx)

To find The comparison between the graph of linear functions.
We will sketch the graph of the functions and then compare.

 

On graphing the functions, we will get

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 1

From the graph, we can see that f(x), and g(x) have different y-intercepts, and h(x), and f(x) have different slopes.
The slope of h(x) is c times the slope of f(x).
And the y−intercept of g(x) is c units more than f(x).

The linear function f(x)=x while comparing to the graphs of
g(x)=f(x)+c and
h(x)=f(cx), has different slopes and intercepts.

Read and Learn More Big Ideas Math Algebra 1 Student Journal 1st Edition Solutions

Its graphical representation is

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 2

 

Page 84  Exercise 2  Answer

Given: Two functions are ​f(x)=x
h(x)\(=\frac{1}{2} x\).

To find The graph of each function on the same coordinate axes.
For finding the nature of the linear equations, let us draw the graphs.

Big Ideas Math Algebra 1 Student Journal 1st Edition Chapter 3 Graphing Linear Functions Exercise 3.6

The graphical representation of the functions f(x)=x and h(x)\(=\frac{1}{2} x\)

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 3

 

From the graph, it is clear that the lines f(x)=x and h(x)\(=\frac{1}{2} x\) intersect with each other. So, The lines have different slopes.

We can conclude the line equations f(x)=x and h(x) \(=\frac{1}{2} x\) intersect and have different slopes. Their graphical representation is

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 5

 

Given: Two functions are ​f(x)=x
h(x)=2x.

To find The graph of each function on the same coordinate axes.
For finding the nature of the linear equations, let us draw the graphs.

 

The graphical representation of the functions f(x)=x and h(x)=2x is

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 5

 

From the graph, it is clear that the lines f(x)=x and h(x)=2x intersect with each other. So, The lines have different slopes.

We can conclude the line equations f(x)=x and h(x)=2x intersect and have different slopes. Their graphical representation is

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 6

 

Given: Two functions are​f(x)=x h(x)-\(=\frac{1}{2} x\).

To find The graph of each function on the same coordinate axes.
For finding the nature of the linear equations, let us draw the graphs.

 

The graphical representation of the functions f(x)=x and h(x)-\(=\frac{1}{2} x\) is

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 7

 

From the graph, it is clear that the lines f(x)=x and h(x)-\(=\frac{1}{2} x\) intersect with each other. So, The lines have different slopes.

We can conclude the line equations f(x)=x and h(x)-\(=\frac{1}{2} x\) intersect and have different slopes. Their graphical representation is

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 8

 

Given: Two functions ​f(x)=x h(x)=−2x.

To find The graph of each function on the same coordinate axes.
For finding the nature of the linear equations, let us draw the graphs.

 

The graphical representation of the functions f(x)=x and h(x)=−2x is

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 9

 

From the graph, it is clear that the lines f(x)=x and h(x)=−2x intersect with each other. So, The lines have different slopes.

We can conclude the line equations f(x)=x and h(x)=−2x intersect and have different slopes. Their graphical representation is

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 10

 

Page 85  Exercise 3  Answer

Given: Two functions​ f(x)=x k(x)=2x−4

To find The graph of each function on the same coordinate axes and which matches the given graphs.
For finding the nature of the linear equations, let us draw the graphs.

 

The graphical representation of the functions f(x)=x and k(x)=2x−4 is

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 11

 

From the graph, it is clear that the lines f(x)=x k(x)=2x−4 intersect with each other.

The graph of k(x)=2x−4. The graphical representation is

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 12

 

Given: Two functions​ f(x)=x k(x)=−2x+2.

To find The graph of each function on the same coordinate axes and which matches the given graphs in the options.
For finding the nature of the linear equations, let us draw the graphs.

 

The graphical representation of the functions f(x)=x and k(x)=−2x+2 is

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 13

 

From the graph, it is clear that the lines f(x)=x and k(x)=−2x+2 intersect with each other.

The graph of k(x)=−2x+2. The graphical representation is

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 14

 

Given: Two functions are​ f(x)=x k(x)\(=\frac{1}{2} x+4\).

To find The graph of each function on the same coordinate axes and which matches the given graphs in the options.
For finding the nature of the linear equations, let us draw the graphs.

 

The graphical representation of the functions f(x)=x and k(x)\(=\frac{1}{2} x+4\).

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 15

 

From the graph, it is clear that the lines f(x)=x and k(x)\(=\frac{1}{2} x+4\) intersect with each other.

The graph of k(x)\(=\frac{1}{2} x+4\) . The graphical representation is.

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 16

 

Given: Two functions are​ f(x)=x k(x)\(=\frac{-1}{2} x-2\).

To find The graph of each function on the same coordinate axes and which matches the given graphs in the options.
For finding the nature of the linear equations, let us draw the graphs.

 

The graphical representation of the functions f(x)=x and k(x)\(=\frac{-1}{2} x-2\) is.

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 17

 

From the graph, it is clear that the lines f(x)=x and k(x)=−2x+2 intersect with each other.

The graph of k(x)\(=\frac{-1}{2} x-2\) . The graphical representation is

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 18

 

Page 85  Exercise 4  Answer

Given: linear function f(x)=x compare to the graphs of
​g(x)=f(x)+c
h(x)=f(C​x)

To find  how the graph of the linear function f(x)=x compares to the graphs of
g(x)=f(x)+c
h(x)=f(C​x) and
Use the given equations to draw the graphs.

 

Graphing the linear function f(x)=x.

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 19

 

Graphing g(x)=f(x)+c

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 20

And h(x)=f(cx)

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 21

As we can see in all three graphs the graphs results are the same. So, all three equations are having same results.

 

The linear function f(x)=x while comparing to the graphs of g(x)=f(x)+c and h(x)=f(cx)

The result we get after graphing is the same.

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 22

f(x)=x

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 23

g(x)=f(x)+c

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 24

h(x)=f(cx)

 

Page 89  Exercise 2  Answer

Given:

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 25

To find Describe the transformation from the graph of f to the graph of g.
Use the given data.

Given graph

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 26

 

The functions are f(x)=−x+1 and g(x)=f(x−2)

Put function f(x)=−x+1 in function g(x).

So we get g(x)=f(x−2)
=f(x)−f(2)…………..(1)
Put x=2 in f(x)=−x+1
f(2)=−2+1
=−1

Put value of f(x) and f(2) in equation (1) , we get
g(x)=−x+1−(−1)​
=−x+1+1
g(x)=−x+2

The graph g(x)=f(x−2) is the vertical translation of graph f(x).

Now, since the slopes are the same, the lines are parallel.

If I take f(x) and translate it up 2 units on the y-axis, I would have g(x) .

The Function g(x)=−x+2 is the transformation from the graph of f to the graph of g.

The Function g(x)=−x+2 is the transformation from the graph of f to the graph of g.

 

Page 89  Exercise 3  Answer

Given:

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 27

 

To find Describe the transformation from the graph of f to the graph of g.
Use the given graph and given equations, to solve.

Given graph

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 28

 

The functions are f(x)=3x and g(x)=f(−x)

Put x=−x in function f(x)=3x , f(−x)=−3x

Put f(−x)=−3x in g(x)

g(x)=−3x

The graph g(x)=f(−x) is the horizontal translation of graph f(x).

Now, since the slopes are not the same, the lines are not-parallel they are crossing each other at point(0,0).

If I take f(x) and translate it Up to 2 units and down−2 units on the x-axis, I would have g(x).

The Function g(x)=−3x is the transformation from the graph of f to the graph of g.

The Function g(x)=−3x is the transformation from the graph of f to the graph of g.

 

Page 89  Exercise 4  Answer

Given: The graphs of the functions as

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 29

The function is, ​g(x)\(=f\left(\frac{1}{2} x\right)\)

\(=\frac{1}{2} x-1\)

We first add the positive number one to the function f(x)=x−1 so the graph is vertically shifted upward by one unit which is the graph of y=x.

Now to this function, we multiply a positive term ​\(\frac{1}{2}\)<1 so that the current graph is compressed vertically by a factor of ​\(\frac{1}{2}\)<1 unit giving us the graph of \(y=\frac{x}{2}\). Add the negative number −1 to it so that the graph is vertically shifted downward by one unit giving us the graph of g(x)\(f\left(\frac{x}{2}\right)\)

 

The given graphs of the functions are as shown.

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 30

The function is ​g(x)=\(f\left(\frac{x}{2}\right)\)

\(=\frac{x}{2}-1\)

The graph of f(x)=x−1 is vertically shifted upward by one unit which is then compressed vertically by a factor of \(\frac{1}{2}\) and finally vertically shifted downward by one unit giving us the graph of g(x)=\(f\left(\frac{x}{2}\right)\)

 

Page 89  Exercise 5  Answer

Given:

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 31

 

To find Describe the transformation from the graph of f to the graph of g.
Use the given data.

Given graph

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 32

The functions are f(x)=x−2 and g(x)=2f(x)

Put f(x)=x−2 in g(x)

So we get, g(x)=2(x−2)
g(x)=2x−4

The graph g(x)=2f(x) is the horizontal translation of graph f(x).

Now, since the slopes are not the same, the lines are not parallel they are crossing each other at point (2,0) .

If I take f(x) and translate it up by-1 unit on the x-axis and down by−2 units on the y-axis, I would have g(x).

The Function g(x)=2x−4 is the transformation from the graph of f to the graph of g.

The function g(x)=2x−4 is the transformation from the graph of f to the graph of g.

 

Page 89  Exercise 7  Answer

Given:f(x)=x and g(x)=3x−2

To find Sketch the graph of the equation.
Use the given data.

 

Given equations,f(x)=x and g(x)=3x−2 Sketching the graph of the above equations using ‘The DESMOS’ Graphing Calculator is

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 33

 

Black line is f(x)=x  , Purple line is g(x)=3x−2

Both the lines cross each other at points (1,1).

The graph g(x)=3x−2 is the vertical translation of graph f(x).

Now, since the slopes are not the same, the lines are not parallel to each other.

If I take f(x) and translate it up−2 and down−2 units on the y-axis, I would have f(x).

And the transformation in equation g(x)=3x−2.

putx=f(x) in the g(x) equation.

g(x)= 3 f(x)-2.

 

The transformation is g(x)=3f(x)−2 and graph of the equations f(x)=x and g(x)=3x−2 is

Big Ideas MathAlgebra 1Student Journal 1st Edition Chapter 3.6 Transformation Of Graph of Linear Functions graph 34

 

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