## Envision Math Grade 8 Volume 1 Chapter 2 Analyze And Solve Linear Equations

**Page 80 Question 1 Answer**

We need to explain how we can analyze connections between linear equations and use them to solve problems.

Equations that consist of degree one is said to be the linear equations.

Linear equations will always result in a straight line when plotted on the graph.

The highest degree of the variables present in the linear equations must be one.

A linear equation must have a constant in it.

Linear equations can be solved by doing arithmetical operations on both sides of the equation.

This will not affect the balance of the equation.It can also be solved graphically.

We can analyze connections between linear equations by solving them arithmetically or by graphically, and we can also use them to solve real life problems.

**Page 83 Exercise 1 Answer**

In an algebraic expression, like terms are terms that have the same variables raised to the same exponent.

Example:

2x^{2}3y

In an algebraic expression, like terms are terms that have the same variables raised to the same exponent.

**Page 83 Exercise 2 Answer**

Quantities that represent an unknown value are variables.

Example:

2x^{3}y2

x and y are the variables.

Quantities that represent an unknown value are variables.

**Page 83 Exercise 3 Answer**

A proportion is a statement that two ratios are equal.

Examples:

\(\frac{1}{3}=\frac{6}{18}\)A proportion is a statement that two ratios are equal.

**Page 83 Exercise 4 Answer**

Operations that ”undo” each other are inverse operations.

Example:

\(\sqrt{x^2}\)Square and square root are inverse operations.

3 + 2 = 5

Inverse operation: 3 – 2 = 1

Operations that “undo” each other are inverse operations.

**Page 83 Exercise 5 Answer**

Given

4x + 7y − 6z + 6y − 9x

To find: Identify Like terms

In an algebraic expression, like terms are terms that have the same variables raised to the same exponent.

4x + 7y − 6z + 6y − 9x

4x And −9x are like terms

7y And 6y are like terms

**Page 83 Exercise 6 Answer**

Given

\(\frac{1}{2} s-(6 u-9 u)+\frac{1}{10} t+2 s\)To find: Identify Like terms

6u And -9u are like terms

**Page 83 Exercise 7 Answer**

Given

2x = 10

Hence, the value of X is 5.

**Page 83 Exercise 8 Answer**

Given

x + 3 = 12

Hence, the value of X is 9.

**Page 83 Exercise 9 Answer**

Given

x − 7 = 1

Hence, the value of X is 8.

**Page 84 Exercise 1 Answer**

We need to write what you already know about the lesson in the third column, Also, we need to write a question that you want to be answered about the lesson. After the lesson, we have to complete the fourth column with the answer to your question.

This entire chapter dealt with analyzing and solving the linear equations.